Suppose 650 mL of hydrogen gas are produced through a displacement reaction involving solid iron and sulfuric acid, H2SO4, at STP. How many grams of iron (II) sulfate are produced? Density H2(g) is on your periodic table.

                      4.415 g of FeSO₄

Explanation:

                   The balance chemical equation for given single replacement reaction is as follow;

                                  Fe + H₂SO₄ → FeSO₄ + H₂

Data Given;

                  Volume =  650 mL  =  0.65 L

                  Density at STP =  0.08988 g/L

                  Mass = Density × Volume = 0.08988 g/L × 0.65 L = 0.0584 g

Step 1: Calculate Moles of H₂ as;  

                  Moles  =  Mass / M.Mass

                  Moles  =  0.0584 g / 2.01 g/mol

                  Moles  =  0.0290 mol of H₂

Step 2: Find out moles of FeSO₄ as;

According to balance chemical equation,

            1 mole of H₂ is produced along with  =  1 mole of FeSO₄

So,

   0.0290 moles of H₂ will be produced along with  =  X moles of FeSO₄

Solving for X,

                    X  =  0.0290 × 1 mol / 1 mol

                    X =  0.0290 moles of FeSO₄

Step 3: Calculate mass of FeSO₄ as;

                   Mass  =  Moles × M.Mass

                   Mass  =  0.0290 mol × 151.90 g/mol

                   Mass  =  4.415 g of FeSO₄

metals are good conductor of electricity. it has free electrons on their surface. according to electron pool theory, each atom present in a metal crystal losses all of its valence electron and as a result a pool of free is form. these pool of electrons are free to move and   conduct electricity easily   while making metal as good conductor.

the correct answer is a. the ability of electrons to flow throughout the metal.

if it's not useful, feel free to report for mistake in answer.