will give branliest!
10 points!
- how many grams of Al2O3 contain 3.45x10^20 atoms of Al2O3?

0.058 g of Al₂O₃

Explanation:

Al₂O₃ → Aluminum oxide

The molar mass is 101.96 g/mol. Therefore 1 mol (NA molecules) are contained in 101.96 grams

NA = Avogadro's number → 6.02×10²³

We make a rule of three to determine the grams we were asked for.

6.02×10²³ molecules are contained in 101.96 g

3.45×10²⁰ molecules will be contained in (3.45×10²⁰ . 101.96 g ) / NA = 0.058 g

11 players on a field that has a maximum of 11 players

weight of any object is given by

w = m*g

where m is mass of the object and g is the acceleration due to gravity.

for earth the value of g is 9.8 m/s^2 so

w=117.6 n m=12 g=?

117.6=12g => g=9.8 m/s^2

which is the force of gravity on earth.