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Chemistry, 19.02.2020 01:52, treymartinez7250
Calculate the number of milliliters of 0.753 M KOH required to precipitate all of the Pb2+ ions in 135 mL of 0.775 M Pb(NO3)2 solution as Pb(OH)2. The equation for the reaction is: Pb(NO3)2(aq) + 2 KOH(aq) Pb(OH)2(s) + 2 KNO3(aq) mL KOH
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Chemistry, 22.06.2019 10:30, officialalex6330
Balance and in which category does it fit in? single or double displacement or synthesis or decomposition? (a) k2 o ā k + o2 (b) na + i2 ā nai (c) cu(no3 )2 + naoh ā cu(oh)2 + nano3 (d) kclo3 ā kcl + o2 (e) ca(no3 )2 + hbr ā cabr2 + hno3 (f) sn(oh)2 ā sno + h2 o (g) p4 + n2 o ā p4 o6 + n2 (h) fe + al2 (so4 )3 ā feso4 + al (i) alcl3 + na2 co3 ā al2 (co3 )3 + nacl (j) c3 h6 + o2 ā co2 + h2 o
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Calculate the number of milliliters of 0.753 M KOH required to precipitate all of the Pb2+ ions in 1...
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