Chemistry, 19.02.2020 01:51, bougiehairstudios
When 9.2 g of frozen N2O4 is added to a 0.50 L reaction vessel and the vessel is heated to 400 K and allowed to come to equilibrium, the concentration of N2O4 is determined to be 0.057 M. Given this information, what is the value of Kc for the reaction below at
400 K? N2O4(g) ⇌ 2 NO2(g)
Answers: 2
for the given reaction is 1.435
= 9.2 g
![K_c=\frac{[NO_2]^2}{[N_2O_4]}](/tpl/images/0515/1174/271f5.png)
![[NO_2]_{eq}=2x=(2\times 0.143)=0.286M](/tpl/images/0515/1174/a94f2.png)
![[N_2O_4]_{eq}=0.057M](/tpl/images/0515/1174/d44e5.png)
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When 9.2 g of frozen N2O4 is added to a 0.50 L reaction vessel and the vessel is heated to 400 K and...
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