Chemistry

Chemistry, 19.02.2020 01:49, mjessen119

Convert the values of Kc to values of Kp or the values of Kp to values of Kc.
A) N2(g)+3H2(g) <--> 2NH3(g); Kc=0.50 at 400 degrees Celsius.
B) H2+I2 <---> 2HI; Kc= 50.2 at 448 degrees Celsius.
C) Na2SO4*10H2O(s) <---> Na2SO4(s)+10H2O(g). Kp=4.08x10^-25 at 25 degrees Celsius.
D) H2O(l) <---> H2O (g); Kp= 0.122 at 50 degrees Celsius.

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Answer

answered: carms12

For A: The value of K_p for the given equation is $1.64\times 10^{-4}$

For B: The value of K_p for the given equation is 50.2

For C: The value of K_c for the given equation is $5.312\times 10^{-39}$

For D: The value of K_c for the given equation is $4.60\times 10^{-3}$

Explanation:

Relation of K_p with K_c is given by the formula:

$K_p=K_c(RT)^{\Delta ng}$ ..........(1)

where,

K_p = equilibrium constant in terms of partial pressure

K_c = equilibrium constant in terms of concentration

R = Gas constant = $0.0821\text{ L atm }mol^{-1}K^{-1}$

T = temperature

$\Delta n_g$ = change in number of moles of gas particles = $n_{products}-n_{reactants}$

For A:

The given chemical equation follows:

$N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g)$

We are given:

$K_c=0.50\\T=400^oC=[400+273]K=673K\\\Delta n_g=2-4=-2$

Putting values in equation 1, we get:

$K_p=0.50\times (0.0821\times 673)^{-2}\\\\K_p=1.64\times 10^{-4}$

Hence, the value of K_p for the given equation is $1.64\times 10^{-4}$

For B:

The given chemical equation follows:

$H_2(g)+I_2(g)\rightleftharpoons 2HI(g)$

We are given:

$K_c=50.2\\T=448^oC=[448+273]K=721K\\\Delta n_g=2-2=0$

Putting values in equation 1, we get:

$K_p=50.2\times (0.0821\times 721)^{0}\\\\K_p=50.2$

Hence, the value of K_p for the given equation is 50.2

For C:

The given chemical equation follows:

$Na_2SO_4.10H_2O(s)\rightleftharpoons Na_2SO_4(s)+10H_2O(g)$

We are given:

$K_p=4.08\times 10^{-25}\\T=25^oC=[25+273]K=298K\\\Delta n_g=10-0=10$

Putting values in equation 1, we get:

$4.08\times 10^{-25}=K_c\times (0.0821\times 298)^{10}\\\\K_c=5.312\times 10^{-39}$

Hence, the value of K_c for the given equation is $5.312\times 10^{-39}$

For D:

The given chemical equation follows:

$H_2O(l)\rightleftharpoons H_2O(g)$

We are given:

$K_p=0.122\\T=50^oC=[50+273]K=323K\\\Delta n_g=1-0=1$

Putting values in equation 1, we get:

$0.122=K_c\times (0.0821\times 323)^{1}\\\\K_c=4.60\times 10^{-3}$

Hence, the value of K_c for the given equation is $4.60\times 10^{-3}$

Answer

answered: Guest

a mercury barometer is a device that uses the physical properties of mercury in a tube to measure barometric pressure. mercury barometers are used for : -

1. measurement of atmospheric pressure

2. determining the altitude of a place

3. weather forecasting

4. calibration and checking of aneroid barometers

5. application in fluid mechanics

6. measurement of pressure in aircrafts

7. surface weather analysis

8. preparation of barographs

9. usage in physical sciences like physics, astronomy & chemistry

10. preparation of aircraft altimeters

characteristics of mercury barometer : -

1.used to define and measure atmospheric pressure.

2.on the average at sea level the column of mercury rises to a height of about 760 mm.

3.this quantity is equal to 1 atmosphere.

4.it is also known as standard atmospheric pressure.

5.a barometer in which the weight of a column of mercury in a glass tube with a sealed top is balanced against that of the atmosphere pressing on an exposed cistern of mercury at the base of the mercury column, the height of the column varying with atmospheric pressure.

Write 15 uses of a mercury barometer along with its characterestics

Answer

answered: Guest

Iwould you figure it out but you don't have a picture or in your question as to what the physical property you're looking for is

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