What is the volume of a solution that has a molarity of 0.600M and contains 4.50 grams of NH4OH?

The volume is 214, 3 ml

Explanation:

We calculate the weight of 1 mol of  NH4OH:

Weight  1 mol NH4OH=  Weight N + (Weight H) * 5 + Weight 0

Weight  1 mol NH4OH= 14g + 1 g* 5 + 16g = 35 g/mol

1 mol NH4OH35 g

0,6mol NH4OHX=(0,6mol NH4OHx 35 g)/1 mol NH4OH= 21 g

We have 0,6 mol in 1000ml of solution (0,600 M)

21g NH4OH1000ml

4,50 g NH4OHx= (4,50 g NH4OH  x 1000ml)/21 g NH4OH= 214, 2857143 ml

i think its 100

i hope this !

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.