One liter of a solution is found to contain 0.022 moles of HCl. Calculate the pH of the solution. Assume complete dissociation.

The pH of the solution is 1.66

Explanation:

Step 1: Data given

Number of moles HCl = 0.022 moles

Molar mass of HCl = 36.46 g/mol

Step 2: Calculate molarity of HCl

Molarity HCl = moles HCl / volume

Molarity HCl = 0.022 moles / 1 L = 0.022 M

[HCl] = [H+] = 0.022 M

Step 3: Calculate pH

pH = -log [H+]

pH = -log(0.022)

pH = 1.66

The pH of the solution is 1.66

1.66

Explanation:

First, we calculate for the molarity of HCl as follows:

Number of mole HCl = 0.022mol

Volume = 1L

Molarity = mole /Volume

Molarity = 0.022mol /1L = 0.022mol/L

The dissociation equation of HCl is given below

HCl <==> H^+ + Cl^-

Since 1mole of HCl dissociate to produce 1 mol of H^+, therefore, 0.022mol/L HCl will also produce 0.022mol/L of H^+

We can obtain the pH is a solution using:

pH = - Log [H^+]

pH = - Log 0.022

pH = 1.66

11 players on a field that has a maximum of 11 players

hurricanes form when warm, moist air from the ocean surface quickly rises into the atmosphere and forms storm clouds and rain. when the clouds are formed, heat is released which warms the cool air in the upper regions of the atmosphere so that the cycle can continue. which two phases of the water cycle are repeated in this process?