Give the stoichiometric coefficient for oxygen when the following equation is balanced using the lowest, whole-number coefficients. CH4O(l) + O2(g) → CO2(g) + H2O(l)

The stoichiometric coefficient for oxygen when the equation is balanced using the lowest whole number coefficients is 3

From the question,

We are to determine the stoichiometric coefficient for oxygen when the given equation is balanced.

The given equation is

CH₄O(l) + O₂(g) → CO₂(g) + H₂O(l)

The balanced equation using the lowest whole number coefficients is

2CH₄O(l) + 3O₂(g) → 2CO₂(g) + 4H₂O(l)

Hence, the stoichiometric coefficient for oxygen when the equation is balanced using the lowest whole number coefficients is 3

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The coefficient for oxygen when the equation is balanced using the lowest, whole-number coefficients is 3.

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

The balanced equation for the given reaction is;

The coefficient for oxygen when the equation is balanced using the lowest, whole-number coefficients is 3.

the answer

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pv=nrt

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