Part A How much time (in minutes) will it take for the water heater to heat the 5.5 L of water from 23 ∘C to 43 ∘C? (Assume that the water has a density of 1.0 g/mL.)

Time = t = 30.01 minutes

Explanation:

The missing part of the question is that "The water heater power rating is 255 Watts, where 1 Watt = 1 J/s.

Firstly, calculating the work done by water heater to heat 5.5 L of water from 23° C to 43°C.

Work Done = Q = m C ΔT

where,

Q = Heat Transfer

m = mass of water

m = Density x Volume = 1 g/mL x 5.5 L = 1000g/L x 5.5L = 5500 g

ΔT = Temperature Difference = 43-23 = 20°C

C = Heat Capacity of Water = 4.186 J/g °C

Therefore,

Since, Power can be given as Work done per unit time,

or, in this case,

Here,

P = 255W or P = 255J (Since 1W = 1J)

3 hours because it is a decent distance.

the ozone layer acts as a filter for the shorter wavelength and highly hazardous ultraviolet radiation (uvr) from the sun, protecting life on earth from its potentially harmful effects. when the sky is clear, there is an inverse relationship between stratospheric ozone and solar uvr measured at the earth's surface.