If atoms in a regular three-dimensional solid are about 10−10m apart, what is the orderof magnitude estimate of the number of atoms in a cube with sides of length 10−2m?(Enter the exponentnfrom your answer of 10n.)(a) 36(b) 24(c) 12(d) 8

(b) 24

Explanation:

Given that:

If atoms in a regular three-dimensional solid are about 10⁻¹⁰ m apart:

Then; the volume of the atom will be (10⁻¹⁰ m)³

= (10⁻³⁰ m)

Since, we were told that the cube have length 10⁻² m .; its volume will also be

= (10⁻² m) ³

= (10⁻⁶ m)

Now, the estimate of the number of atoms in the cube can now be:

=

= 10²⁴

So,we can therefore conclude that our answer is 10²⁴  (Since we are asked to enter it in exponential form)

1.consider the following balanced equation and answer parts a through. show calculations for each part.  

3 ag(s) + 4 hno3(aq) → 3 agno3(aq) + no(g) + 2 h2o(l)  

a. calculate the number of moles of agno3 produced by the reaction of 3 moles of ag with excess hno3. if the number to the left of the compound represents the number of moles of the compound which are present, then 3 moles of ag react with 4 moles hno3 to produce 3 moles agno3 (aq).

so the answer to a would be 3 moles.

b. calculate the number of moles of agno3 produced by the reaction of 108 grams of ag with excess hno3.  

i'm not sure how to plug in the grams of silver into an equation using moles to find how many moles are produced.

c. calculate the number of grams of agno3 produced by the reaction of 108 grams of ag with excess hno3  

d. calculate the number of moles of no produced as a byproduct of the reaction of 108 grams of ag with excess hno3.  

e. calculate the number of grams of no produced as a byproduct starting with 108 grams of ag and excess hno3.  

explanation: