G What is the net yield of NADH when 43 moles of glucose are used to form pyruvate during glycolysis and the pyruvate is reduced during fermentation?

Net NADH = zero

Explanation:

1 mole glucose

=6.02×10^23molecules

=6.02×10^23 × 2

pyruvates + 2 NADH

43 moles of glucose

= 43×12.04×10^23pyruvates

+43×12.04×10^23NADH

2pyruvates uses 2 NADH molecules

43×12.04×10^23 will use 43×12.04×10^23NADH

Hence net NADH produce is zero.

Which means NADH formed during glucose to pyruvate conversion is utilised during fermentation to regenerate NAD+

i do not get it   at all