Calculate the mass in grams of 1.2044 x 10^24 atoms of lead (Pb).

A.) 207.2 g
B.) 2.0 g
C.) 0.50 g
D.) 414.4 g

414.14g

Explanation:

From Avogadro's hypothesis, we understand that 1mole of a substance contains 6.02x10^23 atoms.

From the above, it is evident that 1mole of Pb will also contain 6.02x10^23 atoms.

1mole of Pb = 207g/mol

207g of Pb contains 6.02x10^23 atoms.

Therefore, Xg of Pb will contain 1.2044 x 10^24 atoms i.e

Xg of Pb = (207x1.2044x10^24)/6.02x10^23 = 414.14g