Chemistry, 13.02.2020 18:27, bvallinab

What zone does Earth exist in that potentially allows for life on our planet? Question 2 options: A: Red Zone B: Green Zone C: Goldilocks Zone (Habitable Zone) D: Danger Zone

Answers: 3

Show answers

Answers

answered: aROSSconpollo

Goldilocks Zone

Explanation:

The habitable zone is the area around a star where it is not too hot and not too cold for liquid water to exist on the surface of surrounding planets.

Imagine if Earth was where Pluto is. The Sun would be barely visible (about the size of a pea) and Earth's ocean and much of its atmosphere would freeze. On the other hand, if Earth took Mercury’s place, it would be too close to the Sun and its water would form a steam atmosphere, quickly boiling off. The distance Earth orbits the Sun is just right for water to remain a liquid. This distance from the sun is called the habitable zone, or the Goldilocks zone.

answered: Guest

remember that hf is only the energy of one photon. not two. not three. one. 1) 5.12 * 10^3 photons find the energy of one photon, then determine how many photons are needed to reach the sensitivity. e = hf = (6.626 * 10^-34 js)(5.95 * 10^19 hz) = 3.94247 * 10^-14 j per photon (2.02 * 10^-10 j) / (3.94247 * 10^-14 j/photon) = 5123.69149 photons round to three sig figs. 2) 5.77 * 10^-17 j energy of pulse = energy per photon * number of photons = hfn = (6.626 * 10^-34 js)(1.66 * 10^13 hz)(5250) = 5.774559 * 10^-17 j round to three sig figs. 3) 4.07 * 10^8 kj/mol 10^12 pm = 1 m c = fλ f = c/λ e = hf = hc/λ = [(6.626 * 10^-34 js)(3.00 * 10^8 m/s) / (2.94 * 10^-12 m)](1 kj/1000 j)(6.02 * 10^23 photons/mol) = 40702571.4 kj/mol round to three sig figs. 4) 9.94 * 10^-1 m e = hc/λ λ = hc / e = (6.626 * 10^-34 js)(3.00 * 10^8 m/s) / (2.00 * 10^-25 j) = 0.9939 m round to three sig figs. 5) 9.06 * 10^3 photons energy of pulse = energy per photon * number of photons number of photons = energy of pulse / energy per photon = energy of pulse / (hf) = (3.87 * 10^-13 j) / [(6.626 * 10^-34 js)(6.45 * 10^16 hz)] = 9055.23695 photons round to three sig figs. 6) 2.78 * 10^-15 j this is problem 1, except in reverse. sensitivity = minumum number of photons * energy per photon = (5930)(6.626 * 10^-34 js)(7.077 * 10^14 hz) = 2.78070758 × 10^-15 j round to three sig figs.

answered: Guest

Ithink its called the coefficent.

Other questions on the subject: Chemistry

Chemistry, 23.06.2019 01:00, davelopez979

An unsaturated hydrocarbon is a hydrogen-carbon compound with a. a network solid structure b. single bonds c. single bonds in a branched-chain structure d. double or triple bonds

Answers: 1

continue

Chemistry, 23.06.2019 19:10, jasmine3051

When is the oxidation state of a metal indicated in the name of a compound?

Answers: 2

continue

Chemistry, 23.06.2019 22:30, catchonyet

Identify the limiting reagent and the volume of co2 formed when 11 l cs2 reacts with 18 l o2 to produce co2 gas and so2 gas at stp options: cs2; 5.5l co2 o2; 6.0 l co2 cs2; 11 l co2 o2; 27l co2

Answers: 1

continue

Chemistry, 24.06.2019 00:30, daedae40

Large areas on the leaves of some plants lack chlorophyll and are therefore not green in color. how does this most likely affect photosynthesis? not enough sunlight is captured in these areas of the leaves. carbon dioxide cannot enter these areas of the leaves. too much glucose builds up in these areas of the leaves. oxygen cannot be released in these areas of the leaves.

Answers: 1

continue

Do you know the correct answer?

What zone does Earth exist in that potentially allows for life on our planet? Question 2 options: A:...