Chemistry, 13.02.2020 05:32, Nicoleazaria
A galvanic cell at a temperature of 42 degrees Celcius is powered by the following redox reaction:
3CU2+(aq)+2Al(s)-->3Cu(s)+2Al3+( aq)
Suppose the cell is prepared with 3.43 M Cu2+n one half-cell and 1.63 M Al3+in the other.
Calculate the cell voltage under these conditions. Round your answer to 3 significant digits.
Answers: 3
( × 2)
( × 3)
of the reaction, we use the equation:
![E_{cell}=E^o_{cell}-\frac{2.303RT}{nF}\log \frac{[Al^{3+}]^2}{[Cu^{2+}]^3}](/tpl/images/0509/7294/3aff8.png)
= electrode potential of the cell = ? V![42^oC=[42+273]K=315K](/tpl/images/0509/7294/563a7.png)
![[Cu^{2+}]=3.43M](/tpl/images/0509/7294/455ea.png)
![[Al^{3+}]=1.63M](/tpl/images/0509/7294/1e5e1.png)
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A galvanic cell at a temperature of 42 degrees Celcius is powered by the following redox reaction:
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