1) How many grams of carbon dioxide are produced at the same time as 360 g of water vapor in the
burning of ethane?
2C2H6 + 702 > 4CO2 + 6H2O

3520 g of CO₂

Explanation:

2C₂H₆ + 70₂ → 4CO₂ + 6H₂O

molar ratio of the above reaction is;

2 : 7 → 4 : 6

2 moles of C₂H₆ will form 6 moles of H₂O

Thus, 1 mole of C₂H₆ will form 3 moles of H₂O

mass of H₂O = 360 g

molecular weight of H₂O = 18 g/mol

molar mass = mass ÷ molecular weight = 360÷18 = 20 moles

Total number of moles of H₂O formed = 6 * 20 moles = 120 moles

Number of moles of C₂H₆ reacted = 120 moles ÷ 3 = 40 moles

molar ratio of C₂H₆ to CO₂ = 1 : 2

Thus, number of moles of CO₂ formed = 2 * 40 moles = 80 moles

molecular weight of CO₂ = 44 g/mol

mass of CO₂ formed = number of moles x molecular weight = 80 * 44 = 3520 g

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j