Based on enthalpy of formation data species ∆H◦ f H2S(g) −20.63 kJ/mol O2(g) 0 kJ/mol H2O(ℓ) −285.83 kJ/mol SO2(g) −296.83 kJ/mol calculate ∆Hrxn for 2 H2O(ℓ) + 2 SO2(g) ←→ 2 H2S(g) + 3 O2(g) 1. 562 kJ · mol−1 2. −562 kJ · mol−1 3. −1124 kJ · mol−1 4. 1124 kJ · mol−1

The enthalpy change of the reaction is 1124 kJ

Explanation:

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as

The equation used to calculate enthalpy change is of a reaction is:  

For the given chemical reaction:

The equation for the enthalpy change of the above reaction is:

We are given:

Putting values in above equation, we get:

Hence, the enthalpy change of the reaction is 1124 kJ

a saline water is fed to a reverse osmosis unit at flow rate o rotameter connected to reject (retentate) line reads 8 installed in reject and permeate line reads 15.2 milli siemens/cm and 300 micro siemens/com respectively.

i believe the answer is true.