At constant volume, you cool a sealed, air-filled can, and the pressure reduces by half. What happens in this situation? The number of collisions per unit area doubles. The spaces between the gas molecules shrink. The temperature of the air inside reduces by half. Half of the gas leaks out.

The correct answer to the question is

The temperature of the air inside reduces by half.

Explanation:

The relation to apply here is

(P₁×V₁)/T₁ = (P₂×V₂)/T₂

Thus we have at constant volume

P₁/T₁ = P₂/T₂

Therefore since the pressure reduces by half we have

then P₂ = 0.5 × P₁ or

P₁/T₁ = 0.5 × P₁/T₂ that is 1/T₁ = 0.5/T₂ or T₂ = 0.5 × T₁

The temperature of the air reduces by half

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