A certain liquid has a normal boiling point of and a boiling point elevation constant . A solution is prepared by dissolving some sodium chloride () in of . This solution boils at . Calculate the mass of that was dissolved. Round your answer to significant digits.

The given question is incomplete. The complete question is as follows.

A certain liquid has a normal boiling point of and a boiling point elevation constant . A solution is prepared by dissolving some sodium chloride (NaCl) in 6.50 g of X. This solution boils at . Calculate the mass of NaCl that was dissolved. Round your answer to significant digits.

Explanation:

As per the colligative property, the elevation in boiling point will be as follows.

T = boiling point of the solution =

= boiling point of the pure solvent =

= elevation of boiling constant =

We will calculate the molality as follows.

     molality =

i = vant hoff's factor

As NaCl is soluble in water and dissociates into sodium and chlorine ions so i = 2.

Putting the given values into the above formula as follows.  

                  m = 100 g

Therefore, we can conclude that 100 g of NaCl was dissolved.

how about u try it first

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.