In a quasi-static isobaric expansion, 700 J of work are done by the gas. If the gas pressure is 0.40 atm, what is the fractional increase in the volume of the gas, assuming it was originally at 22.0 L?

Answer : The fractional increase in the volume of the gas is, 1.78

Explanation :

Formula used to calculate the work done by the gas in quasi-static isobaric expansion is:

Isobaric means, at constant pressure.

where,

w = work done by the gas = 700 J = 6.909 L.atm    (1 L.atm = 101.32 J)

p = pressure of the gas = 0.40 atm

= final volume = ?

= initial volume = 22.0 L

Now put all the given values in the above formula, we get:

Now we have to calculate the fractional increase in the volume of the gas.

Fractional increase in the volume of the gas =

Fractional increase in the volume of the gas =

Fractional increase in the volume of the gas = 1.78

Thus, the fractional increase in the volume of the gas is, 1.78

c. because step up transformer steps up the input voltage i.e increases the input voltage  

the number of turns are greater on the secondary side of step up transformer  

transformer does not handle dc current