How many grams of solute are dissolved in 125.0 mL of 5.00 M NaCl (MM = 58.45)?

The amount of solute will dissolve in 125mL of the solution - 36.53g.

Given:

Molarity = 5M

MM of NaCl = 58.45

Solution:

To find the amount of solute in 125 mL of NaCl we need to find the amount of solute the will dissolve in 1 liter.

Molarity = Mass concentration (g/L) / Molar Mass

then, Mass concentration of NaCl = Molarity x Molar Mass

= 5 x 58.45

= 292.25g

So, the 292.25g of solute will diisolve in NaCl 1L

Hence, X gram of NaCl will dissolve in 0.125L of the solution:

=> Xg of NaCl = 292.25 x 0.125

= 36.53g.

Thus, the amount of solute will dissolve in 125mL of the solution - 36.53g.

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36.53g

Explanation:

First we need to find the amount of NaCl that dissolves in 1L of the solution that produced 5M of NaCl

Molarity = 5M

MM of NaCl = 58.45

Molarity = Mass conc (g/L) / MM

Mass conc. (g/L) of NaCl = Molarity x MM

= 5 x 58.45 = 292.25g

Next, we need to find the amount that will dissolve in 125mL(i.e 0.125L)

From the calculations above,

292.25g of NaCl dissolved in 1L

Therefore Xg of NaCl will dissolve in 0.125L of the solution i.e

Xg of NaCl = 292.25 x 0.125 = 36.53g.

Therefore 36.53g of NaCl will dissolve in 125mL of the solution

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