When heated, KClO 3 KClO3 decomposes into KCl KCl and O 2 . O2. 2 KClO 3 ⟶ 2 KCl + 3 O 2 2KClO3⟶2KCl+3O2 If this reaction produced 75.8 g KCl , 75.8 g KCl, how many grams of O 2 O2 were produced?

51.6 g of O₂ are produced in the reaction

Explanation:

The reaction for decomposition is:

2KClO₃ → 2KCl  +  3O₂

Let's convert the mass of the chloride to moles (mass / molar mass):

75.8 g / 74.55 g/mol = 1.016 moles

Ratio is 2:2, so as 2 moles of chloride were produce by 2 moles of chlorate, 1.016 moles of chloride were produced by 1.016 moles of chlorate.

Now we think ratio with O₂, 2:3. Let's make a rule of three:

2 moles of chlorate produce 3 moles of oxygen

1.016 moles of chlorate may produce (1.016 . 3)/2 = 1.614 moles of O₂

Let's convert the moles to mass → 1.614 mol . 32g / 1 mol = 51.6 g

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