An object of mass 10.0 kg is initially at rest. A 100 N force causes it to move horizontally through a distance of 6.00 m. What is the change in the kinetic energy of this object?

The answer to the question is

The change in the kinetic energy of the object is 600 J

Explanation:

The known variables are,

Mass of object, m = 100 kg

Force of object, F = 100 N

The relation for kinetic energy = KE = = 0.5·m·v²

Therefore to find v we first find the acceleration from

F = m·a =10.0 kg × a = 100 N,

Where a = acceleration of the object =100/10 = 10 m/s²

To find the velocity, v, we use the relationship

v² = u² + 2 × a × S, where S is the distance of motion = 6.00 m and u is the initial velocity, u = 0 m/s, therefore

v² = 0 + 2 × 10 m/s² × 6 m = 120 m²/s² or v = 10.95 m/s

Therefore KE = 0.5 × 10 kg × (10.95 m/s)² = 600 J

where the initial velocity, u = 0 m/s

Initial kinetic energy of the object = KE₁ = 0.5 × 10 × 0² = 0

The change in kinetic energy of the object = 600 J - 0 J = 600 J

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