What is the theoretical yield of ammonia (in grams) if 16.55 grams of nitrogen gas and 10.15 grams of hydrogen gas are allowed to react?

Answer : 20.1 grams

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number of particles.

To calculate the number of moles, we use the equation:

     .....(1)

For nitrogen:

For hydrogen gas:

The chemical equation for the reaction is:

By Stoichiometry of the reaction:

1 mole of nitrogen gas reacts with 3 moles of hydrogen.

So, 0.591 moles of nitrogen gas will react with = of hydrogen.

As, given amount of hydrogen is more than the required amount. So, it is considered as an excess reagent.

Thus, nitrogen gas is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

1 mole of nitrogen gas produces 2 moles of ammonia

So, 0.591 moles of  nitrogen gas will produce = of ammonia

Now, calculating the mass of ammonia t:

Thus  theoretical yield of ammonia is 20.1 grams

The theoretical yield of ammonia is 20.13 grams

Explanation:

Step 1: Data given

Mass of N2= 16.55 grams

Mass of H2 = 10.15 grams

Molar mass of N2 = 28 g/mol

Molar mass of H2 = 2.02 g/mol

Step 2: The balanced equation

N2 + 3H2 → 2NH3

Step 3: Calculate moles N2

Moles N2 = mass N2 / molar mass N2

Moles N2 = 16.55 grams / 28.0 g/mol

MolesN2 = 0.591 moles

Step 4: Calculate moles H2

Moles H2 = 10.15 grams / 2.02 g/mol

Moles H2 = 5.02 moles

Step 5: Calculate limiting reactant

For 1 mol N2 we need 3 moles H2 to produce 2 moles of NH3

N2 is the limiting reactant. It will completely be consumed (0.591 moles).

H2 is in excess. There will reat 3*0.591 = 1.773 moles

There will remain 5.02 - 1.773 = 3.247 moles H2

Step 6: Calculate moles of NH3

For 1 mol N2 we need 3 moles H2 to produce 2 moles of NH3

For 0.591 moles N2 we'll have 2-0.591 = 1.182 moles NH3

Step 7: Calculate mass of NH3

Mass NH3 = moles NH3 * molar mass NH3

Mass NH3 = 1.182 * 17.03 g/mol

Mass NH3 = 20.13 grams

The theoretical yield of ammonia is 20.13 grams

2h2o2--> 2h2o + o2

this reaction is of the spontaneous decomposition of hydrogen peroxide down into water and oxygen.

add 2 molecules of hydrogen peroxide and 2 molecules of water. since oxygen is naturally diatomic, the total number of atoms of each element is now the same on both sides of the equation so it is balanced.

this may not be entirely correct but let me know.