How many ions are in 4.26 moles of ammonium

2.57 x 10⁴ ions

Explanation:

Data Given:

no. of moles of ammonium (NH₄) = 4.26 moles

no. of ions of ammonium (NH₄) = ?

Solution:

formula will be used

                no. of moles =  no. of ions/ Avogadro's number

As we have to find number of ions so rearrange the above formula

                no. of ions = no. of moles x Avogadro's number (1)

where

Avogadro's number = 6.022 x 10²³

Put values in the equation 1

              no. of ions = 4.26 mol / 6.022 x 10²³ (ions/mol)

              no. of ions = 2.57 x 10⁴ ions

So,

There are 2.57 x 10⁴ ions in 4.26 moles of ammonium

answer: the enthalpy of the overall chemical reaction is +87.88 kj or +88 kj.

according to hess's law, the overall enthalpy of a reaction is the difference between the sum of enthalpy values of all the products and the sum of enthalpy values of all the reactants.

δh(reaction) = ∑nδh(products) - ∑nδh(reactants)

δh(reaction) = [δh +δh] - [δh]

δh(reaction) = [1(-287.02) + 1(0) ] - [1(-374.9)] kj = +87.88 kj

here, δh (pcl3) = -287.02 kj, δh(cl2) = 0, δh(pcl5) = -374.9 kj

therefore, enthalpy of the overall reaction is +87.88 kj or +88 kj.

the answer is barium and copper bromide