A17.0 g sample of quartz, which has a specific heat capacity of 0.730 jg , is dropped into an insulated container containing 200.0 g of water at 85.0 °c and a constant pressure of 1 atm. the initial temperature of the quartz is 7.2 ℃. assuming no heat is absorbed from or by the container, or the surroundings, calculate the equilibrium temperature of the water. be sure your answer has 3 significant digits. ec

the final temperature T final = 83.863 °C

Explanation:

Assuming that no heat is absorbed from the container , then all the heat absorbed by the water Q water comes from the heat released by the quartz (-Q quatz), since

Q water + Q quatz = Q surroundings =0

denoting w as water and q as quartz then

Q water = mw * cpw * (Tfinal - T initial w)

Q quartz = mq * cpq * (Tfinal - T initial q)

where

m= mass

cp= specific heat capacity at constant pressure

T final = final temperature

T initial w and T initial q = initial temperature of water and quartz respectively

then

mw * cpw * (Tfinal - T initial w) + mq * cpq * (Tfinal - T initial q) = 0

mw * cpw * Tfinal + mq * cpq * Tfinal = mw * cpw *T initial w + mq * cpq * T initial q

Tfinal = (mw * cpw *T initial w+ mq * cpq * T initial q)/(mw * cpw +mq * cpq)

replacing values and assuming cpw= 1 cal/gr°C = 4.186 J/g°C

Tfinal = (200 g * 4.186 J/g°C * 85 °C + 17g * 0.730 J/g°C * 7.2 °C)/(200 g * 4.186 J/g°C + 17g * 0.730 J/g°C) = 83.863 °C

Tfinal = 83.863 °C

if you're asking what comes out, it's steam.

for step 7 table c on the lab "newtons law of action"   the average time it took the car to travel .25 meters   was 1.92 seconds.

the average time it took the car to travel 0.50 meters was 2.61 seconds

hope this : )