Calculate the expansion work done against a constant external pressure of 0.995 atm and at a constant temperature of 19°c. assume that the initial volume of dry ice is negligible and that co2 behaves like an ideal gas.

This is an incomplete question, here is a complete question.

A 19.2 g quantity of dry ice (solid carbon dioxide) is allowed to sublime (evaporate) in an apparatus. Calculate the expansion work done against a constant external pressure of 0.995 atm and at a constant temperature of 22 degrees C. Assume that the initial volume of dry ice is negligible and that CO₂ behaves like an ideal gas.

Answer : The expansion work done is, -1058.33 J

Explanation :

First we have to calculate the volume of gas.

Using ideal gas equation:

where,

P = pressure of gas = 0.995 atm

Conversion used : (1 atm = 760 torr)

V = volume of gas = ?

T = temperature of gas =

R = gas constant = 0.0821 L.atm/mole.K

w = mass of gas = 19.2 g

M = molar mass of carbon dioxide gas = 44 g/mole

Now put all the given values in the ideal gas equation, we get:

Now we have to calculate the work done.

Formula used :

where,

w = work done

p = pressure of the gas = 0.995 atm

= volume = 10.5 L

Now put all the given values in the above formula, we get:

conversion used : (1 L.atm = 101.3 J)

Thus, the expansion work done is, -1058.33 J

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm

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