Problem page a chemist measures the amount of bromine liquid produced during an experiment. he finds that of bromine liquid is produced. calculate the number of moles of bromine liquid produced. round your answer to significant digits.

The question is incomplete, here is the complete question:

A chemist measures the amount of bromine liquid produced during an experiment. She finds that 766.g of bromine liquid is produced. Calculate the number of moles of bromine liquid produced. Round your answer to 3 significant digits.

The amount of liquid bromine produced is 4.79 moles.

Explanation:

To calculate the number of moles, we use the equation:

We are given:

Given mass of liquid bromine = 766. g

Molar mass of liquid bromine, = 159.8 g/mol

Putting values in above equation, we get:

Hence, the amount of liquid bromine produced is 4.79 moles.

h let me think

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.