Calculate the number of grams of xenon in 4.658 g of the compound xenon tetrafluoride.

The number of grams of xenon in 4.658 grams of the compound xenon tetrafluoride is 2.954 grams.

Given the following data:

To determine the number of grams of xenon in 4.658 grams of the compound xenon tetrafluoride:

The chemical formula for xenon tetrafluoride is

First of all, we would calculate the number of moles of .

Number of moles = 0.0225 mole

By stoichiometry:

1 mole of xenon tetrafluoride = 1 mole of xenon

0.0225 mole of xenon tetrafluoride = 0.0225 mole of xenon

To find the mass of xenon:

Substituting the given parameters into the formula, we have;

Mass = 2.954 grams

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The mass of xenon in the compound is 2.950 grams

Explanation:

Step 1: Data given

Mass of XeF4 = 4.658 grams

Molar mass of XeF4 = 207.28 g/mol

Step 2: Calculate moles of XeF4

Moles XeF4 = mass XeF4 / molar mass XeF4

Moles XeF4 = 4.658 grams / 207.28 g/mol

Moles XeF4 = 0.02247 moles

Step 3: Calculate moles of xenon

XeF4 → Xe + 4F-

For 1 mol xenon tetrafluoride, we have 1 mol of xenon

For 0.02247 moles XeF4 we have 0.02247 moles Xe

Step 4: Calculate mass of xenon

Mass xenon = moles xenon * molar mass xenon

Mass xenon = 0.02247 moles * 131.29 g/mol

Mass xenon = 2.950 grams

The mass of xenon in the compound is 2.950 grams

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