Ayield of nh₃ of approximately 98% can be obtained at 200°c and 1,000 atmospheres of pressure. how many grams of n₂ must react to form 1.7 grams of ammonia, nh₃?
a. 0.0058 g
b. 052 g
c. 1.4 g
d. 2.8 g

The mass of nitrogen gas that must be reacted is 1.4 grams

Explanation:

To calculate the number of moles, we use the equation:

     .....(1)

Given mass of ammonia = 1.7 g

Molar mass of ammonia = 17 g/mol

Putting values in equation 1, we get:

The chemical equation for the production of ammonia follows:

By Stoichiometry of the reaction:

2 moles of ammonia is produced by 1 mole of nitrogen gas

So, 0.1 moles of ammonia will be produced from of nitrogen gas

Now, calculating the mass of nitrogen gas from equation 1, we get:

Molar mass of nitrogen gas = 28 g/mol

Moles of nitrogen gas = 0.05 moles

Putting values in equation 1, we get:

Hence, the mass of nitrogen gas that must be reacted is 1.4 grams

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