If 200. ml of water is added to 300. ml of an aqueous solution that is 0.725 m in potassium sulfate, what is the concentration of potassium ions in the final solution?

0.435 M

Explanation:

In case of dilution , the following formula can be used -

M₁V₁ = M₂V₂

where ,

M₁ = initial concentration ,

V₁ = initial volume ,

M₂ = final concentration , i.e. , concentration after dilution ,

V₂ = final volume .

from , the question ,

M₁ =  0.725 M

V₁ = 300 mL

M₂ = ?

V₂ = 300 mL + 200 mL = 500 mL

Since, the final volume of solution would be the summation of the initial and final volume.

Using the above formula , the molarity of the final solution after dilution , can be calculated as ,

M₁V₁ = M₂V₂

0.725 M *  300 mL = M₂ * 500mL

M₂ = 0.435 M

petroleum? coal maybe?

substituting a hydrogen atom with a halogen in a hydrocarbon:

- the single bond remains single. a is wrong.

- the bond with hydrogen is as strong as with a halogen. c is wrong

- a hydrocarbon is saturated if there is no double bond. we do not know that so d is wrong.

- carbon will always have four valence electrons. e is wrong.

by elimination, the correct answer is b. the boiling point of the new compound increases.