Calculate the longest and the shortest wavelength observed in the balmer series of the h atom spectrum

The longest wavelength observed in the Balmer series of the H atom spectrum is 656.3 nm.

The shortest wavelength observed in the Balmer series of the H atom spectrum is 364.6 nm.

Explanation:

Using Rydberg's Equation:

Where,

= Wavelength of radiation

= Rydberg's Constant

= Higher energy level

= Lower energy level

For wavelength to be longest, energy would be minimum, i.e the electron  will jump from third level to second level  :

= Higher energy level =  

= Lower energy level = 2 (Balmer series)

Putting the values, in above equation, we get

The longest wavelength observed in the Balmer series of the H atom spectrum is 656.3 nm.

For wavelength to be shortest, energy would be maximum, i.e the electron  will from infinite level to second level. :

= Higher energy level =  

= Lower energy level = 2 (Balmer series)

Putting the values, in above equation, we get

The shortest wavelength observed in the Balmer series of the H atom spectrum is 364.6 nm.

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.  

they it depends on if one believes about radioactivity, they make a geiger counter beep but maybe it was going to beep anyway electronics do wierd things all the time or it was programmed to beep near certain metals.