Hcl(aq)+naoh(aq)→nacl(aq)+h2o(l)δh° =−57.1kj/molrxn
the chemical equation above represents th...
Chemistry, 23.01.2020 20:31, powellkolbie
Hcl(aq)+naoh(aq)→nacl(aq)+h2o(l)δh° =−57.1kj/molrxn
the chemical equation above represents the reaction between hcl(aq) and naoh(aq). when equal volumes of 1.00mhcl(aq) and 1.00mnaoh(aq) are mixed, 57.1kj of heat is released. if the experiment is repeated with 2.00mhcl(aq), how much heat would be released?
Answers: 3
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