24) which of the following compounds would be least ionic in nature?
a) nacl
b) naf
c) ga2se3
d) zno
e) na3po4

The compound that has been least ionic is . The correct option is C.

Ionic compounds have been formed with the electrostatic interaction between the oppositely charged ions. The ionic bond has been formed by the transfer of electrons.

The ionic strength of the compound can be assessed by the difference in the electronegativity of the atoms involved in the bond.

The difference in electronegativity of the following compounds has been as follows:

A. NaCl

Difference = 3 - 0.9

Difference = 2.1

B. NaF

Difference = 4- 0.9

Difference = 3.1

C.

Difference = 2.4 - 1.6

Difference = 0.8

D. ZnO

Difference = 3.5 - 1.6

Difference = 1.9

E.

Difference = 3.5 - 0.9

Difference = 2.6

The ionic compound with the least difference in electronegativity has been termed to be the least ionic in nature.

The smallest electronegativity difference has been observed in . Thus the compound that has been least ionic is . The correct option is C.

For more information about the ionic strength of the compound, refer to the link:

link

c is the answer because when something is left after something evaporates that shows the chemical change.

"hydrogen bonding is the attraction of h atoms in the water molecule (slight + charge) to o atoms in a neighboring water molecule (slight - charge); it is a weak interatomic force. but it is still strong enough to the water molecules "stick" together."