If 10 grams of carbon dioxide and 5 grams of water are taken into a plant during photosynthesis, what will be the total mass of glucose and oxygen produced?

                       Mass of Glucose  =  6.82 g

Explanation:

                   The balance chemical equation for given reaction is as;

                                    6 CO₂ + 6 H₂O → C₆H₁₂O₆ + 6 O₂

To solve this reaction one should first find the limiting reagent. To do so e will calculate the moles of each reactant as,

Moles of CO₂  =  Given Mass / M.Mass of CO₂

Moles of CO₂  =  10.0 g / 44.0 g/mol

Moles of CO₂  =  0.2272 moles

Similarly for H₂O,

Moles of H₂O  =  Given Mass / M.Mass of H₂O

Moles of H₂O  =  5.0 g / 18.01 g/mol

Moles of H₂O  =  0.2776 moles

Now, according to equation,

            6 mole of CO₂ reacts with  =  6 moles of H₂O

So,

        0.2272 moles of CO₂ will react with  =  X moles of H₂O

Solving for X,

                    X  =  0.2272 moles × 6 moles / 6 mole

                    X  =  0.2272 moles of H₂O

As calculated above, we are provided with 0.2776 moles of H₂O while, we require only 0.2272 moles of it so it means that H₂O is in excess and CO₂ is the limiting reagent hence, CO₂ will control the yield of Glucose.

So,

The amount of Glucose produced is calculated by first finding its moles as,

According to equation,

            6 mole of CO₂ produced  =  1 mole of Glucose

So,

        0.2272 moles of CaSO₄ will produce  =  X moles of Glucose

Solving for X,

                    X  =  0.2272 moles × 1 mole / 6 mole

                    X  =  0.0378 moles of Glucose

Now convert moles of Glucose to mass as,

Mass of Glucose  =  Moles × M.Mass

Mass of Glucose  =  0.0378 × 180.15 g/mol

Mass of Glucose  =  6.82 g

"record the time to complete a chemical reaction" would most likely be part of a lab procedure.