How much salt (in grams) must be added to a two liter bottle of pure water to make the resulting mixture 0.035 percent salt by weight

0.7g of salt.

Explanation:

% concentration by mass =

mass of solute/mass of solution

Solute is the salt

Solution is salt +water

Mass of water = Density of water × volume of water

Mass of water = 1000g/L × 2L

Mass of water = 2000g

Let mass of salt = x

Mass of solution = x+2000

0.035/100 = x/x+2000

0.035(x+2000) = 100x

70= 99.965x

x= 0.7g

Therefore the mass of salt to be added is 0.7g

a). in this case, dh> 0 and sd> 0. if t becomes larger, the term "-tds" will become more negative. at some point, it is possible that -dts will be more negative than the dh is positive, and the reaction will become spontaneous. this is probably the correct answer, but you should look at all of the other possibilities and make sure of that.