Calculate the average atomic mass of the mystery element whose relative intensity data from a mass spectrometer is displayed in the graph.

i totally forgot how to do this, pls show work

giving 30 pts

                      Average Atomic Mass = 10.81

Explanation:

Data Given:

                      Atomic Mass of ¹⁰X  =  10 amu

                      Relative Intensity of ¹⁰X  =  23 %

                      Atomic Mass of ¹¹X  =  11 amu

                      Relative Intensity ¹¹X  =  100 %

It means that if there are 123 atoms of this mystery element then then 23 will be of an isotope with atomic mass of 10 amu and the remaining 100 will be of an isotope with atomic mass of 11 amu.

So, we will now calculate the total mass of all elements as;

                      Total Mass = (23 × 10) + (100 × 11)

                      Total Mass = (230) + (1100)

                      Total Mass = 1330 amu

Then, we will calculate the average mass as,

                      Average Atomic Mass = 1330 / 123

                      Average Atomic Mass = 10.81

answer; i believe that the correct answer is (a) potassium(k)

the correct answer is:

a. formation of precipitation