Determine the value of the equilibrium constant, kgoal, for the reactionn2(g)+h2o(g)⇌no(g)+12n2h4(g ), kgoal=? by making use of the following information: 1. n2(g)+o2(g)⇌2no(g), k1 = 4.10×10−312. n2(g)+2h2(g)⇌n2h4(g), k2 = 7.40×10−263. 2h2o(g)⇌2h2(g)+o2(g), k3 = 1.06×10−10express your answer numerically.

Explanation:

N2(g)+O2(g)⇌2NO(g),

N2(g)+2H2(g)⇌N2H4(g),

2H2O(g)⇌2H2(g)+O2(g),

If we add above reaction we will get:

2N2(g)+2H2O(g)⇌2NO(g)+N2H4(g)                     Eq (1)

Equilibrium constant for Eq (1) is

Divide Eq (1) by 2, it will become:

N2(g)+H2O(g)⇌NO(g)+1/2N2H4(g)                       Eq (2)  

Equilibrium constant for Eq (2) is