An investigation has been completed, similar to the one on latent heat of fusion, where steam is bubbled through a container of water. steam condenses and the lost energy heats the water and container. given the following data, do the calculations requested.
mass of the aluminum container 50 g
mass of the container and water 250 g
mass of the water 200 g
initial temperature of the container and water 20â°c
temperature of the steam 100â°c
final temperature of the container, water, and condensed steam 50â°c
mass of the container, water, and condensed steam 261g
mass of the steam 11g
specific heat of aluminum 0.22 cal/gâ°c

heat energy gained by the container

a. 770 cal
b. 550 cal
c. 330 cal
d. 220 cal

c. 330 cal

Explanation:

Given the information from the question. We need to calculate heat energy gained by the container

The formula to be used is Q=M*C*(Change in T).  Where Q= heat energy gained by the container, M= mass of aluminum, Change in T = Change in temperature and T = Specific heat of aluminum.

Now we have Q=M*C*(Change in T) = 50g*0.22*(50-20) = 330 cal

The correct answer is option c. 330 cal.

the best answer is d because the strong cohesion is caused by the ability of water molecules to undergo hydrogen bonding.

a is incorrect because when water solidifies, it becomes   ice, which expands and occupies a bigger volume for the same mass of water in its liquid state.

b is incorrect because water has high surface tension. besides bonding to itself it hydrogen bonds to other molecules at the top decreasing possibility for breaking of attractive forces.

c is incorrect because the water molecule has oxygen which is highly electronegative and so pulls the electron pair towards itself creating a dipole moment, making the molecule polar.

e is incorrect because water has strong adhesion, ability to stick to other molecules such as glass because of this molecules having stronger hydrogen bonding than water.