Calculate the number of so2 molecules formed when 14 s8 molecules and 184 o2 molecules react

112 molecules are formed from the reaction

Explanation:

Let's make the reaction:

S₈ + 8O₂  → 8SO₂

1 mol of S₈ reacts with 8 moles of O₂ to produce 8 moles of sulfur dioxide

Let's determine the moles ( amount of molecules / NA)

14 / 6.02x10²³ = 2.32x10⁻²³ mol of S

184 / 6.02x10²³ = 3.05x10⁻²² mol of O₂

As ratio is 1:8, the limiting reactant would be the sulfur. It's obviouly I do not have enough the amount of molecules.

8 mol of O₂ need 1 mol of S₈

3.05x10⁻²² mol of O₂ would need (3.05x10⁻²² / 8) = 3.81ₓ10²¹

Now, that we get the limiting, we can work with the reaction

1 mol of S₈ produce 8 mol of dioxide

Then, 2.32x10⁻²³ mol of S will produce (2.32x10⁻²³ . 8) = 1.85x10⁻²² moles of SO₂

Let's convert the moles in, amount of molecules (mol . NA)

1.85x10⁻²² mol . 6.02x10²³ = 112 molecules

c. because step up transformer steps up the input voltage i.e increases the input voltage  

the number of turns are greater on the secondary side of step up transformer  

transformer does not handle dc current