Using an extinction coefficient of 15,000 m-1cm-1, calculate the concentration (in mm) of a molecule with an absorbance value of 0.200. you can assume the standard cuvette pathlength of 1 cm.

0.013 mM

Explanation:

Our strategy to solve this question will be to utilize Beer-Lambert law:

A = ε c L where  A is the absorbance,

                           ε  is the extinction coefficient (M⁻¹cm⁻1),

                           c is the concentration (in M)

                           L  is the cuvette path length  (in cm)

so the concentration, c,  from this equation will be given by

c = A/ ( ε L)

we have all the required values, thus

c= 0.200 / ( 15000 M⁻¹ cm⁻1 x 1 cm ) = 1.3 x 10⁻⁵ M

Now we are being asked to give the concentration in mmol ( 1 mol = 1000 mmol) per liter, so we need to convert our concentration:

1.3 x 10⁻⁵ mol/L x  1000 mmol/mol =  0.013 mmol/L = 0.013 mM

c. heat could easily travel through the molecules in the air and escape/enter the flask. removing the air slows down the heat transfer.  

  the   balanced   equation   for   reaction of   ca metal   with   o2 to   produce   cao   is as below

2 ca+ o2→ 2 cao2

  explanation

the reaction is   balanced     since the   number of atoms   in reactant side is   equal to   number of atoms   in   product side.   for   example   they   are 2   atom of   ca in   reactant   side   and   2   atoms of ca   in   the product side.

  the   process   is a   meet the   requirement   of   redox   reaction because :     calcium   is   oxidized   from   oxidation state 0   to 2+   while   oxygen   is reduced from   oxidation   state   0   to 2-