Given stock solutions of glucose (1m), asparagine (100 mm), and nah2po4 (50 mm), how much of each solution would you need to prepare 500 ml of a reagent that contains 0.05 m glucose, 10 mm asparagine, and 2 mm nah2po4?

25 mL,50 mL, 20 mL

Explanation:

Molarity = numbers of mole / volume in liters

Glucose

stock solutions concentration = 1M

concentration needed = 0.05 M

volume of the preparation = 500ml = 500 / 1000 = 0.5l

number of moles of glucose in the solution = Molarity × molar mass = 0.05 × 0.5 L = 0.025 moles

volume of  the stock needed = number of moles / molarity of the stock solution = 0.025 moles / 1 M = 0.025L = 25 mL

Asparagine

Molarity of the stock solution = 100mM = 0.1 M

Molarity needed = 10mM = 0.01 M

volume of the prepared solution = 0.5 L

number of moles in the prepared solution = 0.01 M × 0.5 L = 0.005 moles

volume of the stock solution needed = number of moles of the prepared solution / Molarity of the stock = 0.005 / 0.1 = 0.05L = 50 mL

NaH₂PO₄

Molarity of the stock solution = 50 mM = 0.05 M

Molarity of the needed = 2 mM = 0.002 M

Volume of the prepared solution = 0.5 L

number of moles in the prepared solution = 0.002 M × 0.5 L = 0.002 × 0.5 L = 0.001 moles

volume of the stock needed = 0.001 moles / 0.05 M = 0.02 L = 20 mL

alkaline metals are lithium, sodium, rubidium, potassium, cesium and francium.

alkali metals have electronegativity from 0.7 to 1, lowest in periodic table of elements, which means that alkali metals (i group in periodic table) has positive oxidation number in compounds.

electronegativity is a chemical property that describes the tendency of an atom to attract a shared pair of electrons towards itself.

alkaline metals (far left in main group) have lowest ionizations energy and easy remove valence electrons,

for example, potassium is the alkali metal and has a single valence electron in the outer electron shell.

electron configuration of potassium is: ₁₉k 1s²2s²2p⁶3s²3p⁶4s¹.

they can not exist alone in nature, because they are very reactive.

the answer would be a