Lithium and nitrogen react in a combination reaction to produce lithium nitride: 6li (s) + n2 (g) â 2li3n (s)in a particular experiment, 4.50-g samples of each reagent are reacted. the theoretical yield of lithium nitride is g. lithium and nitrogen react in a combination reaction to produce lithium nitride: 6li (s) + n2 (g) 2li3n (s)in a particular experiment, 4.50-g samples of each reagent are reacted. the theoretical yield of lithium nitride is g. a) 3.76b) 22.6c) 4.53d) 7.52e) 11.2

The answer to your question is letter D

Explanation:

Data

mass of Li = 4.5 g

mass of N₂ = 4.5 g

limiting reactant = ?

Reaction

                         6Li (s)   +   N₂ (g)   ⇒  2Li₃N

This reaction is balanced

Process

1.- Calculate the molecular mass of the reactants

Li = 7 x 6 = 42g

N = 14 x 2 = 28 g

Calculate the limiting reactant using proportions

Theoretical proportion    Li / N = 42 / 28 = 1.5

Experimental proportion   Li/N  = 4.5/4.5 = 1

As the experimental proportion was lower than the theoretical, the limiting reactant is Lithium

2.- Calculate the theoretical yield of Li₃N

                        42 g of lithium  70 g of Li₃N

                        4.5 g of lithium   x

                        x = (4.5 x 70) / 42

                        x = 315 / 42

                        x = 7.5 %

no but i do not usually comment or use my voice that much when it comes to social media