Asolution is made by mixing of acetyl bromide and of heptane . calculate the mole fraction of acetyl bromide in this solution. be sure your answer has the correct number of significant digits.

The question is incomplete, here is the complete question:

A solution is made by mixing 127.g of acetyl bromide and 90.g of heptane . Calculate the mole fraction of acetyl bromide in this solution. Round your answer to 3 significant digits.

The mole fraction of acetyl bromide is 0.534 and heptane is 0.466

Explanation:

To calculate the number of moles, we use the equation:

     .....(1)

Given mass of acetyl bromide = 127. g

Molar mass of acetyl bromide = 123 g/mol

Putting values in equation 1, we get:

Given mass of heptane = 90. g

Molar mass of heptane = 100.2 g/mol

Putting values in equation 1, we get:

Mole fraction of a substance is given by:

For acetyl bromide:

For heptane:

Hence, the mole fraction of acetyl bromide is 0.534 and heptane is 0.466