Rank the following compounds in order of decreasing boiling point: potassium bromide (kbr), acetylene (c2h2), and chloromethane (ch3cl)

KBr , CH3Cl, C2H2

Explanation:

Chloro-methane or Chloroform exist as a dense liquid, acetylene as a gas used for welding purpose and potassium bromide is a crystalline solid, the states of matter of each of them gives us a clue of how strong the bonds between them are , acetylene having the weakest bond as its a gas and KBr having the strongest bond for its crystalline solid state. The boiling point of each compound is given below;

C2H2 =61.2°C

CH3Cl =-192.2°C

KBr =1435°C

answer

i think the answer is a) as air pressure in an area increases, the density of the gas particles in that area decreases.

hope it

you need to have a picture of the atom that way we can answer it