Calculate îgârxn for the following reaction:
4co(g)+2no2(g)â4co2(g)+n2(g).
use the following reactions and given îgârxn values:
a. 2no(g)+o2(g)â2no2(g), îgârxn= - 72.6 kj
b. 2co(g)+o2(g)â2co2(g), îgârxn= - 514.4 kj
c. 12o2(g)+12n2(g)âno(g), îgârxn= 87.6 kj

-1043,8 KJ

Explanation:

Hello!

It is necessary to accommodate the reactions to get the reaction of my interest.

Reaction A reverses what modifies its energy in its sign (+72.6 KJ).

Reaction B doubles, which also doubles its energy (-514.4 KJ x 2).

Reaction C reverses what modifies its energy in its sign (-87.6 KJ).

By sum of the energies I get the energy of the global reaction.  

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the number of valence electrons for each molecule or ion is shown beneath the structure. remember hydrogen will not have more than two electrons. this hydrogen is part of a covalent bond (sharing two electrons). a double bond here would cause hydrogen to share four electrons with phosphorus.