If 1.54 miles of gas occupy a volume of 383.2l, what will be the volume of 6.4 moles?

V₂ =  1592.32 L

Explanation:

Given data:

Initial number of moles = 1.54 mol

Initial volume = 383.2 L

Final volume = ?

Final number of moles = 6.4 mol

Solution:

Formula:

V₁/n₁ = V₂/n₂

V₁ = Initial volume

n₁ = initial number of moles

V₂ = Final volume

n₂ =  Final number of moles

now we will put the values in formula.

V₁/n₁ = V₂/n₂

383.2 L / 1.54 mol = V₂/ 6.4 mol

V₂ = 248.8 L/mol ×6.4 mol

V₂ =  1592.32 L

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml