Agold ingot weighs 5.50 ibs. if the density of gold is 19.31 g/cm^3, and the length and width of the ingot are 12.0 cm and 3.00 cm respectively, what is the height of the ingot? a) 3.59 cm b) 1.34 times 10^3 cm c) 10.2 cm d) 6.50 times 10^-3 cm

A) 3.59 cm

Explanation:

Given that :-

The density of the gold ingot =

Given that:- Mass = 5.50 lbs

Also, considering the conversion of lbs to g as shown below:-

1 lb = 453.592 g

Thus,

Mass = = 2494.756 g

The volume = Length*Breadth*Height

Given that:- Length = 12.0 cm , Breadth = 3.00 cm

Considering the expression for density as:-

Solving for height, we get that:-

Height=3.59 cm

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explanation:

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