Asolution of methanol, ch3oh, in water is prepared by mixing together 128 g of methanol and 108 g of water. the mole fraction of methanol in the solution is closest to

Mole fraction of methanol = 0.4

Explanation:

Molar mass methanol: 32 g/mol

Molar mass water: 18 g/m

Mol = Mass / Molar mass

128 g / 32 g/m = 4 moles of CH₃OH

108 g / 18 g/m = 6 moles of H₂O

Mole fraction of methanol = Moles of methanol / Moles of methanol + Moles of H₂O

4 / 10 = 0.4

The mole fraction of methanol is  0.4

The molar mass of methanol is = 32 g/mol

The number of moles of methanol is = 128 g/32 g/mol = 4 moles

The molar mass of water is 18 g/mol

The number of moles of water = 108 g/18 g/mol = 6 moles

Total number of moles = 6 moles + 4 moles = 10 moles

Mole fraction of methanol = 4 moles/ 10 moles = 0.4

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for step 7 table c on the lab "newtons law of action"   the average time it took the car to travel .25 meters   was 1.92 seconds.

the average time it took the car to travel 0.50 meters was 2.61 seconds

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