9. calculate the percentage composition of silver sulfate, ag2so4.

69% Ag, 10.5% S, 20.5% O.

Explanation:

Ag₂SO₄ → Molar mass = 311.8 g/mol

2 mol of Ag → 107.87g/m . 2m = 215.74 g

1 mol of S → 32.06g/m . 1m = 32.06 g

4 mol of O → 16g/m  .4m = 64 g

Percentage composition will be:

(Mass of Ag/ Total mass) . 100

(215.74 g / 311.8 g) . 100 = 69 %

(Mass of S/ Total mass) . 100

(32.06 g / 311.8 g) .100 = 10.5%

(Mass of O/ Total mass) . 100

(64 g / 311.8 g) . 100 = 20.5 %

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