How many moles of nitrogen would react with excess hydrogen to produce 520 ml of ammonia?
a) 0.0116 mol
b) 0.012 mol
c) 0.0232 mol
d) 0.024 mol

The balanced reaction is:

N2 + 3H2 = 2NH3

We are given the amount of the product to be produced.This will be the starting point of our calculations. 1.    We use the ideal gas equation to find for the number of moles.

n = PV / RT = 1.00(.520 L) / (0.08206 atm L/mol K ) 273 K
n= 0.0232 mol NH3

0.0232 mol NH3 (1 mol N2 / 2 mol NH3) = 0.0116 mol N2

Therefore, the correct answer is A.

The answer to this problem is. 67